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Category:Programming languages Category:Programming languages created in 1982 Category:Bengali Category:Educational software for WindowsQ: What's wrong with this linked list implementation? I tried to implement a simple linked list in C, following the examples on a book. The output of the program is gibberish, with a segmentation fault. The book doesn't elaborate on how to debug those kind of errors. This is my code: #include #include struct node { int value; struct node *next; }; typedef struct node node; struct node *create_node(int val) { struct node *n; n = (node*)malloc(sizeof(node)); n->value = val; n->next = NULL; return n; } void print_list(struct node *head) { struct node *temp; while(head) { temp = head; printf("%d ", temp->value); head = head->next; } } int main(int argc, char *argv[]) { struct node *head; head = create_node(10); head->next = create_node(20); head->next->next = create_node(30); head = head->next; head->next->next->next = create_node(40); print_list(head); return 0; } A: You are never assigning the head->next to anything, hence the segfault. A: You have a couple of problems. Firstly, you need to set the next pointer in the create_node function, otherwise it remains NULL. Secondly, you are assigning a local pointer to the head pointer in main, which won't be visible to the print_list function. Example of corrected code


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